Question

aThe hypotenuse of a right triangle is 15 centimeters long. One leg is9 centimeters long. How long is the other leg?

Answer 1

Using pythagorean theorem:

$\begin{gathered} c^2=a^2+b^2 \\ 15^2=9^2+b^2 \\ solve_{\text{ }}for_{\text{ }}b\colon \\ b=\sqrt[]{15^2-9^2} \\ b=\sqrt[]{225-81} \\ b=\sqrt[]{144} \\ b=12 \end{gathered}$

The other leg is 12cm long