The function:
[tex]f(x)=x^2+3[/tex]has the form:
[tex]f(x)=ax^2+bx+c[/tex]with a = 1, b = 0, and c = 3.
The equation of the axis of symmetry is calculated as follows:
[tex]x=\frac{-b}{2a}[/tex]Substituting with a = 1, b = 0, we get:
[tex]\begin{gathered} x=\frac{-0}{2\cdot1} \\ x=0 \end{gathered}[/tex]
