Question

Find the acceleration of a toy place whose velocity as a function of time is given by the graph belowat a) t = 4.00 s b) t = 9.00 s and c) t = 11.0 s.

Answer 1

ANSWER:

a) 1 m/s^2

b) -4 m/s^2

c) 0 m/s^2

STEP-BY-STEP EXPLANATION:

The acceleration is given by the following equation:

$a=\frac{\Delta v}{\Delta t}=\frac{v_f-v_i}{t_f-t_i}$

Therefore:

a) t = 4 s

$a=\frac{3-(-3)}{6}=\frac{3+3}{6}=\frac{6}{6}=1$

b) t = 9 s

$a=\frac{-5-3}{10-8}=\frac{-8}{2}=-4$

c) t = 11 s

$a=\frac{-5-(-5)}{12-10}=\frac{-5+5}{2}=\frac{0}{2}=0$