Question

The following data was collected when a reaction was performed experimentally in the laboratory.Reaction Data ReactantsProductsAl(NO3)3NaClNaNO3AlCl3Starting Amount in Reaction4 moles9 moles??Determine the maximum amount of NaNO3 that was produced during the experiment. Explain how you determined this amount

Answer 1

The first step to solve this question is to write and balance the chemical equation that describes the reaction:

$Al(NO_3)_3+3NaCl\to3NaNO_3+AlCl_3$

According to the given information the limiting reactant is NaCl, this is because 9 moles of this reactant react with 3 moles of Al(NO₃)₃.

Use this information to find the maximum amount of NaNO₃ that was produced:

$9molNaCl\cdot\frac{3molNaNO_3}{3molNaCl}=9molNaNO_3$

It means that 9 moles of NaNO₃ are produced.