Given:
the perimeter of an isosceles triangle 30cm
The length of each congruent side is 3cm more than the length of its base.
Let the length of the base side = x
So, the length of each congruent side = x + 3
the perimeter is the sum of the lengths of the sides of the triangle
So,
[tex](x+3)+(x+3)+x=30[/tex]Solve the equation to find the value of x
[tex]\begin{gathered} x+3+x+3+x=30 \\ 3x+6=30 \\ 3x=30-6 \\ 3x=24 \\ \\ x=\frac{24}{3}=8 \end{gathered}[/tex]So, the length of the base side = 8 cm
And the length of each congruent side = 8 + 3 = 11 cm
So,
The lengths of all sides are: 11 cm, 11 cm and 8 cm