Given
The formula
[tex]\begin{gathered} \text{The volume of a cone =}\frac{1}{3}\pi r^2h \\ \\ \pi=3.14 \\ r=5 \\ h=6 \end{gathered}[/tex][tex]\begin{gathered} \text{The volume of a cone =}\frac{1}{3}\pi r^2h \\ \text{The volume of a cone =}\frac{1}{3}\times3.14\times5^2\times6 \\ \\ \text{The volume of a cone =}\frac{1}{3}\times3.14\times25^{}\times6 \\ \\ \text{The volume of a cone =}\frac{1}{3}\times3.14\times150 \\ \\ \text{The volume of a cone =}3.14\times50 \\ \\ \text{The volume of a cone =}157yd^3 \end{gathered}[/tex]
The final answer
[tex]\text{The volume of a cone =}157yd^3[/tex]
