Answer: x = -1/2 and x = -3
Given the following quadratic function
[tex]2x^2\text{ + 7x + 3 = 0}[/tex][tex]\begin{gathered} \text{The standard form of a quadratic function is given as} \\ ax^2\text{ + bx + c = 0} \\ \text{a = 2 , b = 7 and c = 3} \\ \text{ find ac} \\ ac\text{ = 2 x 3} \\ ac\text{ = 6} \\ \text{ Find the factors of ac (6) when add that will give us 7x} \\ \text{The factor is 6 and 1} \\ 2x^2\text{ + 6x + x + 3 = 0} \\ 2x(\text{x + 3) + 1 (x + 3)} \\ (2x\text{ + 1) = 0 or (x + 3) = 0} \\ 2x\text{ + 1 = 0 or x+ 3 = 0} \\ \text{x = -1/2 or x = -3} \end{gathered}[/tex]The solution of the above quadratic function is x = -1/2 and x = -3
