Respuesta :

given the equation:

y = 5/4x - 3

to complete the table for the values of x and y using intergers

fristly,

when x = -4

y = 5/4(-4) - 3

y = -5 - 3

y = -8

when x = 0

y = 5/4(0) - 3

y = 0 - 3

y = -3

when = 4

y = 5/4(4) - 3

y = 5 - 3

y = 2

when x = 8

y = 5/4(8) - 3

y = 5(2) - 3

y = 10 - 3

y = 7

so completing the table:

y = 5/4x - 3

x y

-4 -8

0 -3

4 2

8 7

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