Question

Given the right triangle below, if AB = 9 and BC = 14, find AC. (round to nearest whole number)

Answer 1

Given:

Find-:

The value of "AC"

Explanation-:

Use the Pythagoras theorem:

$\text{ Hypotenuse}^2=\text{ Base}^2+\text{ Perpendicular}^2$

Where,

$\begin{gathered} \text{ Hypotenuse }=AC \\ \\ \text{ Base }=BC \\ \\ \text{ Perpendicular }=AB \end{gathered}$

Apply the Pythagoras then,

$AC^2=BC^2+AB^2$$\begin{gathered} AC^2=9^2+14^2 \\ \\ AC^2=81+196 \\ \\ AC^2=277 \\ \\ AC=\sqrt{277} \\ \\ AC\approx16.64 \end{gathered}$

The value of AC is 17.