Question

A screw from the space shuttle in outer space falls from the space shuttle. How far would the screw travel in 11 seconds?

Answer 1

$\begin{gathered} \sqrt[]{d}=t\times2.8 \\ \sqrt[]{d}=11\times2.8 \\ \sqrt[]{d}=30.8 \\ d=30.8^2 \\ d=948.6 \end{gathered}$

the screw far would travel 948.6