Question

5 A B B 3 C Find tan(B) in the triangle.

Answer 1

We will solve as follows:

*We will use the law of sines to determine the value of beta, that is:

$\frac{3}{\sin(\beta)}=\frac{5}{\sin (90)}$

Now, we solve for beta:

$\Rightarrow\sin (\beta)=\frac{3\sin(90)}{5}\Rightarrow\sin (\beta)=\frac{3}{5}$$\Rightarrow\beta=\sin ^{-1}(\frac{3}{5})$$\Rightarrow\tan (\beta)=\frac{3}{4}$