In order for the parallelogram tobe a square, x = [?].4x + 1712x - 23

By definition, the diagonals of a square bisect each other, so these diagonals are perpendicular, which means that they form a Right angle (90 degrees) when they intersect. The diagonals of a square have equal length.
In this case, you in order for the parallelogram to be a square:
[tex]4x+17=12x-23[/tex]Then, you can solve for the variable "x":
[tex]\begin{gathered} -12x+4x=-23-17 \\ -8x=-40 \\ \\ x=\frac{-40}{-8} \\ \\ x=5 \end{gathered}[/tex]Therefore, the answer is:
[tex]x=5[/tex]