Given the following equation:
[tex]\text{ x}^2\text{ -4 = 5}[/tex]
Let's determine the solution,
[tex]\text{ x}^2\text{ -4 = 5}[/tex][tex]\text{ x}^2\text{ - 4 + 4 = 5 + 4}[/tex][tex]\text{ x}^2\text{ = 9}[/tex][tex]\text{ }\sqrt{\text{x}^2}\text{ = }\sqrt{\text{9}}[/tex][tex]\text{ x = }\pm\text{ 3}[/tex]
Therefore, there are two possible solutions in the equation. x = 3 or -3.
The answer is Choice A : ± 3
