Find the vertical asymptotes of the functionOA. x =OB. x =OC.x =-2, x =-2, x=-2, x =OD. x = -2, x =Reset Selection1, x = 2-1, x = 1, x = 3/2, x = 2-4/3, x = -1, x = 3/2-4/34(x+2)(x+1)(3x+4)(2x-3)3(x-2)(x²-1)(2x-3)(x+2)**

Find the vertical asymptotes of the functionOA x OB x OCx 2 x 2 x2 x OD x 2 x Reset Selection1 x 21 x 1 x 32 x 243 x 1 x 32434x2x13x42x33x2x12x3x2 class=

Respuesta :

A vertical asymptote occurs when the function is divided by zero.

Thus, we have to evaluate the denominator.

In order for the denominator to be zero, one of the factors of the multiplication (in the denominator) must be zero.

So,

(a) x - 2 = 0

(b) x² - 1 = 0

(c) 2x - 3 = 0

(d) x + 2 =0

Let's isolate the x in the equations above to find the asymptotes.

(a) Adding 2 to both sides:

x - 2 + 2 = 0 +2

x = 2

(b) Adding 1 to both sides and then taking the square root:

x² - 1 + 1 = 0 + 1

x² = 1

√x² = ±√1

x² = ±1

(c) Adding 3 to both sides and then dividing the sides by 2:

2x - 3 + 3 = 0 + 3

2x = 3

2x/2 = 3/2

x = 3/2

(d) Subtracting 2 to both sides:

x + 2 - 2 = 0 - 2

x = -2

Answer: The vertical asymptotes are:

x = -2, x = -1, x = 1, x = 3/2, x = -2

RELAXING NOICE
Relax