The calorimeter constant of the given system is 140.8 J/°C
The temperature of warm water = 76°C
The volume of the warm water = 75 ml
The temperature of the cold water = 21°C
The volume of the cool water = 50 ml
The final temperature of the water = 47°C
The warm water lost is given by
q = m Δt Cₚ
where q is the heat loss/gain
m is the mass of the water
Δt is the temperature difference
Cₚ is the Specific heat
q = 75 x (76 - 47) x 4.184
= 75 x 29 x 4.184
= 9,100.2 J
The Coldwater gain is given by
q = m Δt Cₚ
= 50 x (47 - 21) x 4.184
= 50 x 26 x 4.184
= 5,439.2 J
The calorimeter got the rest at
9,100.2 - 5,439.2 = 3,661 J
Therefore, the calorimeter constant is
= Calorimeter gain/temperature rise
= 3,661 / 26
= 140.8 J/°C
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