Question

Enter an equation in point-slope form for the line.(0, 3) and (2,6) are on the line.An equation of the line in point slope form is:

Answer 1

The Point-Slope form of an equation of the line, is:

$y-y_1=m\mleft(x-x_1\mright)$

Where "m" is the slope and this is a point of the line:

$(x_1,y_1)$

The formula for calculate the slope, is:

$m=\frac{y_2-y_1}{x_2-x_1}$

In this case, you can set up that:

$\begin{gathered} y_2=6 \\ y_1=3 \\ x_2=2 \\ x_1=0 \end{gathered}$

Substituting values, you get that the slope of the line is:

$\begin{gathered} m=\frac{6-3}{2-0} \\ \\ m=\frac{3}{2} \end{gathered}$

Knowing the slope and the point (2,6), you can susbtitute values into the equation in Point-Slope form shown at the beginning of the explanation.

Therefore, the answer is:

$y-6_{}=\frac{3}{2}(x-2)$