Question

Which one has the largest minor arc? (Blue arc) 80 279.5° (5x + 29)

Answer 1

the first blue arc is 80°

for the second one we get

$2x+7x-9=360\rightarrow9x=351\rightarrow x=\frac{351}{9}=39$

therefore the blue arc is 78°

for the third circle we get that blue arc is:

$360-279.5=80.5^{\circ}$

for the last one we get:

$5x+29+2x-19=360\rightarrow7x=350\rightarrow x=\frac{350}{7}=50$

so the arc is:

$100-19=81$

so the largest minor arc is the one that measure 81. So the last circle