Question

Hey can you pleas help me on this problem thank you

Answer 1

Step 1:

Divide the figure into parallelogram, trapezium and a rectangle.

Step 2:

Find the area of each figure

Area of parallelogram A

$\begin{gathered} \text{Area of parallelogram = Base }\times\text{ Height} \\ =\text{ 4 }\times\text{ 3} \\ =12in^2 \end{gathered}$

Area of rectangle B with dimension 18 in by 4 in

$\begin{gathered} \text{Area of rectangle B = Length }\times\text{ Breadth} \\ =\text{ 18 }\times\text{ 4} \\ =72in^2 \end{gathered}$

Find the area of trapezium C

$\begin{gathered} \text{Area of trapezium = }\frac{1}{2}(a\text{ + b)}\times h\text{ } \\ \text{a = 1 , b = 2 , h = 4} \\ \text{Area of trapezium = }\frac{1}{2}(1\text{ + 2)}\times4\text{ } \\ \text{Area of trapezium = }\frac{12}{2}\text{ } \\ \text{Area of trapezium = }6in^2 \end{gathered}$

Final answer

The area of the figure is the sum of the area of the trapezium, parallelogram and rectangle.

= 6 + 72 + 12

= 90