Question

Find the volume and surface area of a rectangular box 4ft by 3.2 ft by 7 ft.

Answer 1

Answer:

The volume of the rectangular box is;

$89.6\text{ }ft^3$

The Surface area of the rectangular box is;

$126.4\text{ }ft^2$

Explanation:

Given a rectangular box with dimensions;

$\begin{gathered} l=4ft \\ b=3.2ft \\ h=7ft \end{gathered}$

Recall that the volume of a rectangular box can be calculated using the formula;

$V=l\times b\times h$

Substituting the given values;

$\begin{gathered} V=4\times3.2\times7\text{ }ft^3 \\ V=89.6\text{ }ft^3 \end{gathered}$

Therefore, the volume of the rectangular box is;

$89.6\text{ }ft^3$

The surface area of a rectangular box can be calculated using the formula;

$S=2(lb+bh+lh)$

Substituting the given values;

$\begin{gathered} S=2(4(3.2)+3.2(7)+4(7)) \\ S=2(63.2) \\ S=126.4\text{ }ft^2 \end{gathered}$

Therefore, the Surface area of the rectangular box is;

$126.4\text{ }ft^2$