Solution:
[tex]\begin{gathered} \text{Let the number of students in vans be represented by v} \\ \text{Let the number of students in buses be represented by b} \end{gathered}[/tex]
Given:
[tex]\begin{gathered} \text{High school A filled 11 vans and 9 buses with 352 students. This means;} \\ 11v+9b=352\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots(1) \\ \\ \text{High school B filled 11 cans and 3 buses with 220 students. This means;} \\ 11v+3b=220\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots(2) \end{gathered}[/tex]Solving both equations simultaneously by subtracting equation (2) from equation (1);
[tex]\begin{gathered} \text{Equation (1)-(2);} \\ 11v-11v+9b-3b=352-220 \\ 6b=132 \\ \text{Dividing both sides by 6;} \\ b=\frac{132}{6} \\ b=22 \\ \\ \\ \text{Substituting b in equation (2) to get the value of v;} \\ 11v+3b=220 \\ 11v+3(22)=220 \\ 11v+66=220 \\ 11v=220-66 \\ 11v=154 \\ \text{Dividing both sides by 11,} \\ v=\frac{154}{11} \\ v=14 \end{gathered}[/tex]Therefore,
The number of students in each van is 14 students
The number of students in each bus is 22 students.
OPTION A is the correct answer.