Question

How many solutions does the following function have? 2x^2-3x+1=0

Answer 1

The given expression is

$2x^2-3x+1=0$

Let's use the discriminant to know the number of solutions.

$b^2-4ac$

Where a = 2, b = -3, and c = 1.

$(-3)^2-4\cdot2\cdot1=9-8=1$

This means the equation has two real solutions.