From the question,
We are given the equation
[tex]3+7m=4m+3(m+1)[/tex]
First, we will expand the RHS of the equation
This will give
[tex]3+7m=4m+3m+3[/tex]
By simplifying the RHS we will get
[tex]3+7m=7m+3[/tex]
From the equation above, the terms on the LHS equal to the terms on the RHS
This implies that the equation has infinite number of solutions
That is, if we insert any value the equation will always be true
