Respuesta :

[tex]\begin{gathered} The\text{ standard form a +bi=} \\ \frac{9}{3\text{ -i}}= \\ \frac{9\text{ }}{3\text{ - i}}(\frac{3\text{ +i}}{3\text{ +i}})= \\ \frac{27\text{ + 9i}}{9\text{ - i}^2}= \\ \frac{27\text{ + 9i}}{9\text{ -\lparen-1\rparen}}= \\ \frac{27\text{ + 9i}}{9\text{ +1}}= \\ \frac{27\text{ + 9i}}{10} \\ standard\text{ a + bi form:} \\ \frac{27}{10}\text{ + }\frac{9i}{10} \end{gathered}[/tex]

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