Answer:
[tex]112xy-16x+128x^2-14y=(8x-1)(14y+16x)[/tex]Explanation: We need to factor following completely, it is done by Grouping method, which means that we group the similar terms and then start factoring:
[tex]112xy-16x+128x^2-14y[/tex]Factorization by Grouping is as follows:
[tex]\begin{gathered} 112xy-16x+128x^2-14y \\ \text{ Grouping}\rightarrow \\ \\ y(112x-14)-16x+128x^2\rightarrow14y(8x-1)+16x(-1+8x) \\ \text{ Factoring out the (8x-}1) \\ \rightarrow112xy-16x+128x^2-14y=(8x-1)(14y+16x) \\ \end{gathered}[/tex]Therefore the final answer is again:
[tex]112xy-16x+128x^2-14y=(8x-1)(14y+16x)[/tex]