We have the expression:
[tex]2y=-3+x[/tex]lets divide all by 2, this way our equation will be in a better form to understand it:
[tex]y=\frac{1}{2}x\text{ -}\frac{3}{2}[/tex]lets find where this line cuts the X axis and Y axis, wich means, find the point with X=0 and other point with Y=0, as follows:
[tex]\text{If y=0, we have 0=}\frac{1}{2}x\text{ -}\frac{3}{2}\text{ }\rightarrow\text{ }\frac{3}{2}=\frac{1}{2}x\text{ }\rightarrow\text{ x=3}[/tex]so, our graph has the point (3,0), now lets find where it cuts the X axis:
[tex]\text{If x=0, we have y=}\frac{1}{2}(0)\text{ -}\frac{3}{2}\text{ }\rightarrow\text{ y=}\frac{-3}{2}[/tex]So, our graph has the point (0,-3/2), with those informations, lets draw our graph: