Respuesta :

Geometric Sequence

[tex]\begin{gathered} a_n=a_1\cdot r^{n-1} \\ \end{gathered}[/tex]

Where:

[tex]\begin{gathered} a_n=n^{th}\text{ term} \\ a_1=first^{}\text{ term} \\ r=\text{ common ratio} \end{gathered}[/tex][tex]an=40\cdot\sqrt[]{2}^{n-1}[/tex]

Therefore

[tex]a_1=40[/tex][tex]r=\sqrt[]{2}[/tex]

Answer: Letter B

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