Geometric Sequence
[tex]\begin{gathered} a_n=a_1\cdot r^{n-1} \\ \end{gathered}[/tex]Where:
[tex]\begin{gathered} a_n=n^{th}\text{ term} \\ a_1=first^{}\text{ term} \\ r=\text{ common ratio} \end{gathered}[/tex][tex]an=40\cdot\sqrt[]{2}^{n-1}[/tex]Therefore
[tex]a_1=40[/tex][tex]r=\sqrt[]{2}[/tex]Answer: Letter B