The magnitude of the magnetic force produced on a current carrying wire with current I and length L which is placed in a region with a magnetic field B that forms an angle θ with the wire is given by:
[tex]F=ILB\sin\theta[/tex]Replace I=6A, L=0.15m, B=0.4T and θ=30º to find the magnitude of the force on the wire:
[tex]F=(6A)(0.15m)(0.4T)\sin(30º)=0.18N[/tex]Therefore, magnitude of the force on the wire is equal to 0.18N.
