a) To find the probability that the score is higher than 300 you have to find the Z-score for 300, by using the formula:
[tex]\begin{gathered} Z=\frac{x-\mu}{\sigma} \\ Z=\frac{300-300}{35}=\frac{0}{35}=0 \end{gathered}[/tex]The probability of x>300 P(z>0)=1-P(z<=0)
Using the Standard Normal Cumulative Probability Table, P(z<=0)=0.5
Then,
[tex]P(Z>0)=1-0.5=0.5[/tex]Now, you can do the same to find the probability that the score is higher than 335, let' see:
[tex]Z=\frac{335-300}{35}=\frac{35}{35}=1[/tex]The probability of x>335 is P(Z>1), then
[tex]P(Z>1)=1-P(Z\leq1)=1-0.8413=0.1587[/tex]These results mean that it is a 50% of probability that the score of the student chosen is greater than 300, and a 15.87% of probability that the score is greater than 335.
b) SRS=4, their mean score will be the same as the mean of the population = 300, the standard deviation of the sample is the standard deviation of the population divided by √n (n is the size of the sample=4).
[tex]\mu=300\text{ and }\sigma=\frac{35}{\sqrt[]{4}}=17.5[/tex]c) The probability that the mean score for the SRS is higher than 300 is:
[tex]\begin{gathered} Z=\frac{x-\mu}{\sigma} \\ Z=\frac{300-300}{17.5}=\frac{0}{17.5}=0 \end{gathered}[/tex][tex]P(Z>0)=1-P(Z\leq0)=1-0.5=0.5[/tex]The probability that the mean score for the SRS is higher than 335 is:
[tex]Z=\frac{335-300}{17.5}=2[/tex][tex]P(Z>2)=1-P(Z\leq2)=1-0.9772=0.0228[/tex]These results mean that it is a 50% of probability that the mean score of the SRS is greater than 300, and a 2.28% of probability that the mean score is greater than 335.