Question

A 2300-kg truck is traveling down a highway at 32 m/s. What is the kinetic energy of the truck?

Answer 1

ANSWER:

1177600 joules

STEP-BY-STEP EXPLANATION:

Given:

m = 2300 kg

v = 32 m/s

We can calculate the kinetic energy using the following formula:

$E=\frac{1}{2}m\cdot v^2$

Replacing:

$\begin{gathered} E=\frac{1}{2}\cdot2300\cdot32^2 \\ E=1177600\text{ J} \end{gathered}$

The kinetic energy of the truck is 1177600 joules.