Question

Find the volume of a pyramid with a square base, where the side length of the base is 17 in and the height of the pyramid is 9 in. Round your answer to the nearest tenth of a cubic inch Answer: in Submit Answer attempt 1 out of 2

Answer 1

Knowing that it is a Regular square pyramid, you can use the following formula for calculate its volume:

$V=\frac{Bh}{3}$

Where "B" is the area of the base and "h" is the height of the pyramid.

The area of square can be found with this formula:

$A=s^2$

Where "s" is the length of any side of the square.

In this case you know that the side length of the base is:

$s=17in$

Therefore, its area is:

$B=(17in)^2=289in^2$

According to the information given in the exercise:

$h=9in$

Knowing "B" and "h", you can substitute values into the formula and then evaluate, in order to calculate the volume of this pyramid. This is:

$\begin{gathered} V=\frac{(289in^2)(9in)}{3} \\ \\ V=\frac{2601in^3}{3} \\ \\ V=867in^3 \end{gathered}$

The answer is:

$867in^3$