Question

Complete the table by evaluating the function h(x)=(2x+4)2 for the given values of x.

Answer 1

Given

$h(x)=(2x+4)^2$

1) x=-2,

$\begin{gathered} h(-2)=(2(-2)+4)^2=(-4+4)^2=0^2=0 \\ \Rightarrow h(-2)=0 \end{gathered}$

2) x=0,

$\begin{gathered} h(0)=(2\cdot0+4)^2=4^2=16 \\ \Rightarrow h(0)=16 \end{gathered}$

3) x=1

$h(1)=(2\cdot1+4)^2=6^2=36$