i have to use trig ratios to find the unknown angle or side length in the following problem.

Using trigonometric ratios
[tex]\sin 53=\frac{opposite}{\text{hypotenuse}}[/tex]Therefore,
[tex]\begin{gathered} \sin 53=\frac{x}{15} \\ x=15\sin 53 \\ x=15\times0.79863551004 \\ x=11.9795326507 \\ x=12.0 \end{gathered}[/tex]