Solution
- The population function is:
[tex]\begin{gathered} f(x)=3.478(1.023)^x \\ where, \\ x\text{ is the number of years after 1899} \end{gathered}[/tex]- Thus, to find the number of people, 65 year olds and older, present at 2010, we perform the following steps:
[tex]\begin{gathered} x=2010-1899 \\ x=111 \\ \\ \therefore f(x)=3.478(1.023)^{111} \\ \\ f(x)=43.4\text{ Million} \end{gathered}[/tex]Final Answer
The answer is 43.4 Million