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Answer:
The recursive formula is given below as
[tex]\begin{gathered} a_1=7 \\ a_n=-3+a_{(n-1)} \end{gathered}[/tex]Step 1:
To figure out the value of the forurth term, we will substitute the value of
[tex]n=4[/tex]By substituting the n=4, we will have
[tex]\begin{gathered} a_{n}=-3+a_{(n-1)} \\ a_4=-3+a_{(4-1)} \\ a_4=-3+a_3 \end{gathered}[/tex]Step 2:
Calculate the second term and the third term
[tex]\begin{gathered} a_{n}=-3+a_{(n-1)} \\ a_2=-3+a_{(2-1)} \\ a_2=-3+a_1 \\ a_2=-3+7 \\ a_2=4 \\ \\ a_{n}=-3+a_{(n-1)} \\ a_3=-3+a_{(3-1)} \\ a_3=-3+a_2 \\ a_3=-3+4 \\ a_3=1 \end{gathered}[/tex]Step 3:
Substitute the value of the third term in the equation below
[tex]\begin{gathered} a_{4}=-3+a_{3} \\ a_4=-3+1 \\ a_4=-2 \end{gathered}[/tex]Hence,
The final answer is
[tex]\Rightarrow-2[/tex]OPTION C is the right answer