System A:
[tex]\begin{gathered} I)\text{ }y=-\frac{3}{2}x-4 \\ II)\text{ }3x+2y=-8 \end{gathered}[/tex]
Multiplying equation I by 2 we got:
I) 2y = -3x - 8
II) 3x + 2y = -8
Adding 3x on both sides of equation we got:
I) 3x + 2y = -8
II) 3x + 2y = -8
Since both equations are equivalent, this system must have infinitely many solutions. Therefore, it is a consistent dependent system.
System B:
I) y = -3x + 1
II) y = -3x
If we subtract equation II from equation I we reach the absurd statement "0 = 1". Theirefore, this is an inconsistent system.
System C:
[tex]\begin{gathered} I)\text{ }y=-\frac{1}{2}x+\frac{5}{2} \\ II)\text{ }y=-2x+7 \end{gathered}[/tex]
Multiplying equation I by 2 we got:
I) 4y = -2x + 10
II) y = -2x + 7
Subtracting equation II from equation I we got:
3y = 3
y = 1
Then we have:
1 = -2x + 7
2x = 6
x = 3
Since this system has only one solution, it is a consistent independent system, with solution (3,1).