Given 9 x^2 - y^2 = 9
Divide both sides by 9, we have:
[tex]\begin{gathered} \frac{x^2}{1}\text{ - }\frac{y^2}{9}\text{ = 1} \\ (\text{ a,b ) = (1, 9) , radius = 1} \\ \end{gathered}[/tex]Axes of symmetry
There are two lines about which a hyperbola is symmetrical.
For the standard hyperbola y=1x, we see that if we replace x⇒y and y⇒x, we get y=1x. Similarly, if we replace x⇒−y and y⇒−x, the function remains the same.
Therefore the function is symmetrical about the lines y=x and y=−x.
The lines of symmetry are ; x = 0, y=0.
