Find the value of X in the length of VR

Since V is between R and T, then:
[tex]RT=VR+VT\text{.}[/tex]Substituting VR=3x, VT=5x+9, RT=33, and solving for x we get:
[tex]\begin{gathered} 33=3x+5x+9, \\ 33=8x+9, \\ 33-9=8x, \\ 8x=24, \\ x=3. \end{gathered}[/tex]Substituting x=3 in VR we get:
[tex]\text{VR}=3\cdot3=9.[/tex]Answer:
The value of x is 3.
The length of VR is 9.