Question

Determine the temperature Kelvin of CO2(g) having a root mean square velocity of 4.37 * 10 ^ 2 m/s

Answer 1

Answer:

The temperature is 336.9K.

Explanation:

To calculate the temperature of CO2, it is necessary to replace the values of CO2 molar mass (0.044kg/mol), gas constant (R=8.314J/mol.K) and in this case the root mean square velocity (4.37x10^2m/s) in the root mean square velocity formula:

$\begin{gathered} V_{rms}=\sqrt{\frac{3*R*T}{m}} \\ 4.37*10^2\frac{m}{s}=\sqrt{\frac{3*8.314\frac{J}{mol*K}*T}{0.044\frac{kg}{mol}}} \\ (4.37*10^2\frac{m}{s})^2=\frac{3*8.314\frac{J}{mol*K}*T}{0.044\frac{kg}{mol}} \\ 190,969\frac{m^2}{s^2}=566.86\frac{J}{kg*K}*T \\ \frac{190,969\frac{m^2}{s^2}}{566.86\frac{J}{kg*K}}=T \\ 336.9K=T \end{gathered}$

So, the temperature is 336.9K.