Respuesta :
To find how much water does the tank still need for it to be filled, we just need to subtract from the total capacity the amount poured by Alejandro and Anthony in the tank. The value filled by Alejandro is given, 2 11/15 liters. Anthony poured 1 3/5 less than Alejandro into the tank, this means the amount of water poured by Anthony is 2 11/15 liters minus 1 3/5 liters.
Doing this calculation, we have
[tex]\begin{gathered} 2\frac{11}{15}-1\frac{3}{5}=2+\frac{11}{15}-(1+\frac{3}{5}) \\ =2+\frac{11}{15}-1-\frac{3}{5} \\ =1+\frac{11}{15}-\frac{3}{5} \\ =1+\frac{11}{15}-\frac{3}{5}\cdot\frac{3}{3} \\ =1+\frac{11}{15}-\frac{9}{15} \\ =1+\frac{11-9}{15} \\ =1+\frac{2}{15} \\ =1\frac{2}{15} \end{gathered}[/tex]This means Anthony poured 1 2/15 liters of water. Adding this value with the amount of water Alejandro filled, we have
[tex]1\frac{2}{15}+2\frac{11}{15}=(1+2)(\frac{2+11}{15})=3\frac{13}{15}[/tex]And finally, subtracting this amount from the total capacity of the tank(8 liters), we have
[tex]\begin{gathered} 8-3\frac{13}{15}=8-(3+\frac{13}{15}) \\ =8-3-\frac{13}{15} \\ =5-\frac{13}{15} \\ =5\cdot\frac{15}{15}-\frac{13}{15} \\ =\frac{75}{15}-\frac{13}{15} \\ =\frac{75-13}{15} \\ =\frac{62}{15} \\ =\frac{60+2}{15} \\ =\frac{60}{15}+\frac{2}{15} \\ =4+\frac{2}{15} \\ =4\frac{2}{15} \end{gathered}[/tex]It is needed 4 2/15 liters of water to fill the tank.
