To draw a line on the plane, we need two points on it.
Calculating two points of the equation y=x/3+6
[tex]\begin{gathered} x=0 \\ \Rightarrow y=0+6=6 \\ \to(0,6) \\ \text{and} \\ x=3 \\ \Rightarrow y=\frac{3}{3}+6=7 \\ \to(3,7) \end{gathered}[/tex]Two points of the equation y=x/6+5
[tex]\begin{gathered} x=0 \\ \Rightarrow y=0+5=5 \\ \to(0,5) \\ x=6 \\ \Rightarrow y=\frac{6}{6}+5=6 \\ \to(6,6) \end{gathered}[/tex]Then, the equation of the line y=x/3+6
And the equation of y=x/6+5 is
To solve the equation, graph both equations at the same time and look for the intersection point, as shown below
The solution is (x,y)=(-6,4)