Given the following system of equations:
[tex]\begin{cases}3x+2y=-12 \\ 2x+y=4\end{cases}[/tex]We will solve the system by elimination as follows:
[tex]\begin{gathered} \begin{cases}3x+2y=-12 \\ 2x+y=4\operatorname{\rightarrow}(*-2)\end{cases} \\ ============= \\ \begin{cases}3x+2y=-12 \\ -4x-2y=-8\end{cases} \\ ============= \\ -x=-20 \\ x=20 \end{gathered}[/tex]Substitute x = 20 into the second equation to find (y):
[tex]\begin{gathered} 2(20)+y=4 \\ 40+y=4 \\ y=4-40=-36 \end{gathered}[/tex]So, the value of y = -36
The answer will be option A. -36
