Solve for x:
[tex]\begin{gathered} \frac{1}{5}x+3x=2x+42 \\ \frac{1}{5}x+3x-2x=42 \\ (\frac{1+3\cdot5-2\cdot5}{5})x=42 \\ \frac{1+15-10}{5}\cdot x=42 \\ \frac{6}{5}x=42 \\ x=42\cdot\frac{5}{6}=\frac{210}{6}=35 \end{gathered}[/tex]The value of x is x=35.
