SOLUTION:
Case: Proof of similar triangles
Given:
Two triangles
GI is parallel to NT
Required: To proof that triangles GIA and TNA are similar
Method:
Step 1:
First the angles at A are equal
Step 2: The angles at I and N are same. The angles at G and T are the same. Reason: This is because they are formed by alternate angles
Step 3: This is an AA condition.
Because all the angles per triangle are equal.
Final answer:
Therefore:
[tex]\Delta GIA\text{ = }\Delta TNA[/tex]
