The given inequality :
[tex]-3x\ge9[/tex]Simplify :
Multiply both side by (-1) and reverse the inequality :
[tex]\begin{gathered} -3x\ge9 \\ (-1)(-3x)\leq(-1)9 \\ 3x\leq(-9) \end{gathered}[/tex]
Divide the inequality by 3:
[tex]\begin{gathered} \frac{3x}{3}\leq\frac{(-9)}{3} \\ x\leq(-3) \end{gathered}[/tex]
i.e. x is less than or equal to (-3)
Solution : x ≤ (-3)
so,
x is lies in the half open interval of - infinity to (-3)
Interval Notation : (-infinity, -3]
Answer:
Solution : x ≤ (-3)
Interval Notation : (-infinity, -3]
