Given:
Initial velocity = 4.10 m/s
Mass of tongue, = 0.410 g
Mass of the rest of frog, = 13.0 g
Let's find the recoil speed of the frog and the lily pad.
Apply the Law of Conservation of Momentum:
[tex]v(m_1+m_2)=m_Tv_T[/tex]Rewrite the formula for v:
[tex]v=\frac{m_Tv_T}{m_1+m_T}[/tex]Where:
mT is the mass of tongue = 0.410g = 0.000410 kg
vT = 4.10 m/s
m1 = 13.0 g = 0.013 kg
Hence, we have:
[tex]\begin{gathered} v=\frac{0.410\times4.10}{13.0+0.410} \\ \\ v=0.125\text{ m/s}\approx0.13\text{ m/s} \end{gathered}[/tex]Therefore, the recoil speed of the frog and lily pad is 0.13 m/s
ANSWER:
0.13 m/s