Question

2). Scientists measure a bacteria population and find that it is 10,000. Five dayslater, they find that the population has doubled. Which function f could describethe bacteria population d days after the scientists first measured it, assuming itgrows exponentially?*f(d) = 10,000-20f (d) = 10,000 (12)O a).Ob).

Answer 1

Given data:

The initial population is 10,000.

The pouplation after 5 days is 2(10,000)=20,000.

Substitute 0 for t in the first option.

$\begin{gathered} P=10,000(2)^0 \\ =10,000 \end{gathered}$

Substitute 5 for t in the first option.

$\begin{gathered} P=10,000(2)^5 \\ =320,000 \end{gathered}$

Substitute 5 for t in the second option.

$\begin{gathered} P^{\prime}=10,000(\sqrt[5]{2})^5 \\ =20,000 \end{gathered}$

Thus, the option (b) is correct.