Starting from rest, a 2-kilogram block of wood slides adistance of two meters down a frictionless slope, asshown.KE= 1 mov12.0e2 kg2 m1 mWhat is the approximate kinetic energy of the woodenblock at the bottom of the slope?C. 200J D. 400JA. 20J B. 40J

Starting from rest a 2kilogram block of wood slides adistance of two meters down a frictionless slope asshownKE 1 mov120e2 kg2 m1 mWhat is the approximate kinet class=

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Answer:

A. 20 J

Explanation:

By the conservation of energy, the kinetic energy at the bottom of the slope is equal to the potential energy at the top of the slope. Then, we can write the following equation

KE = PE

KE = mgh

Where m is the mass, g is the gravity and, and h is the height

Replacing m = 2 kg, g = 10 m/s², and h = 1 m, we get:

KE = (2 kg)(10 m/s²)(1 m)

KE = 20 J

Therefore, the answer is

A. 20 J

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