What are the coordinates ofthe terminal point determined by t= 11(pi)/3

SOLUTION
The equation given is
[tex]t=\frac{11\pi}{3}[/tex]By the definitions of trigonometry functions, the point t has as coordinates
[tex]t(x,y)[/tex]Where
[tex]\begin{gathered} x=\cos \theta \\ y=\sin \theta \\ \text{and } \\ \theta=\frac{11\pi}{3} \end{gathered}[/tex]The next step is to convert the angle to degree
[tex]\frac{11\pi}{3}=\frac{11\times180}{3}=660^0[/tex]Then we have
[tex]\begin{gathered} x=\cos 660^0\text{=}\frac{1}{2} \\ y=\sin 660^0=-\frac{\sqrt[]{3}}{2} \end{gathered}[/tex]Hence the terminal point becomes
[tex](x,y)=(\frac{1}{2},-\frac{\sqrt[]{3}}{2})[/tex]Therefore the right option is C