Geometry question about trig ratios Solve for x. Round to the nearest tenth.

Explanation:
To get the value of x, we will use the trigonometric ratio
[tex]\cos \theta=\frac{adjacent}{hypotenuse}[/tex]The value of x will be obtained as
[tex]\cos 64^0=\frac{x}{11}[/tex]Making x, the subject of the formula
[tex]\begin{gathered} x=11\times\cos 64^0 \\ x=4.8\text{ (To the nearest tenth)} \end{gathered}[/tex]The value of x is 4.8 (To the nearest tenth)