Answer:
temperature = 1.05 K
Explanation:
We are told to find the temperature of a 2.33 mol gas that has a volume of 4.5 L with a pressure of 4.55 kPa.
To solve this problem, we need to use the ideal gas law. which is expressed in the formula:
[tex]\boxed{PV = nRT}[/tex],
where:
• P = pressure in Pascals
• V = volume in m³
• n = number of moles
• R = molar gas constant (8.31 J/K · mol)
• T = temperature in Kelvin (K)
First, let's convert the pressure and volume into the units required by the formula:
○ pressure = 4.55 kPa = 4550 Pa (multiplying by 1000)
○ volume = 4.5 L = 0.0045 m³ (dividing by 1000)
Now we can substitute this data into the above formula and solve for T:
[tex]PV = nRT[/tex]
⇒ 4500 × 0.0045 = 2.33 × 8.31 × T
⇒ 20.25 = 19.3623T
⇒ T = [tex]\frac{20.25 }{19.3623}[/tex]
⇒ T = 1.05 K (3 s.f.)
Therefore, the temperature of the gas is 1.05 K.
